ZENITHAL GNOMONIC EQUATORIAL PROJECTION FOR THE CONTIENT SOUTH AMERICA AND AFRICA
EXERCISE
:Prepare
a graticule on the Gnomonic Equatorial Projection for the continent of South America at scale 1:150,000,000 and
interval 10˚.
INTRODUCTION:
In gnomonic projection source of light is always in centre of the globe. The
equatorial case of the projection is used to represent a hemisphere. The polar
case is used to show the northern and southern hemispheres whereas the
equatorial case is used to show the eastern and western hemispheres.
CONSTRUCTION:
Radious
of the reduce earth is 250×106 /150× 106 = 1.66//
In the diagram -
NESQ = the reduced
globe
EQ = The Equator
NAES = The central
meridian
NOS = The axis of the
Earth
OE = The radious of the
reduced globe.
A = Any point on the
Earth’s surface at ɸ˚ latitude along the central meridian
B = Any point on the
Earth’s surface at at θ latitude and θ longitude (Zero).
C = Any point on the
Earth’s surface at at ɸ˚ latitude and θ
longitude
TEP = Tangent plane at
the equator.
The main problem in
drawing the graticules on the projection are-
a] To
find out the distance of any parallel (ɸ˚) from the equator along the central
meridian = A/ E
b] To
find out the distance of any meridian (θ˚) from the central meridian along the
equator = EB/
c] To
find out the distance of any parallel ɸ˚
from the equator along any meridian (θ˚) =B/C/
To find out the
distance A/ E,
considering the right triangle OEA/
AE/OE= tan ɸ˚
AE/OE= tan ɸ˚= R tan ɸ˚
To find out the distance A/ E, considering the right
angle triangle OEB/
EB/
/OE= tan θ
EB/
= OE tan θ˚
EB/ = OE tan θ˚= R
tan θ
OB//OE=sec θ˚
OB/=OE sec θ˚ R sec θ˚
Now considering the right angled triangle ∆ OBC
B/C//OB/= tan ɸ˚ or
BC=OB tan ɸ˚=R sec θ˚ tan
ɸ˚
B/C//OB/=
tan ɸ˚=R sec θ˚ tan ɸ˚
Spacing between meridian along equator and between
parallel along central meridian is-
R
|
ɸ˚
|
tan ɸ
|
R tan ɸ˚
|
10˚
|
.17
|
2. 92
|
|
20˚
|
.36
|
.60
|
|
1.66
|
30˚
|
.57
|
.95
|
40˚
|
.83
|
1.39
|
|
50˚
|
R
|
R
|
sec θ
|
ɸ
|
tan θ
|
R sec
θ tan θ
|
10˚
|
.17
|
.28
|
|||
20˚
|
.36
|
.60
|
|||
10˚
|
1.01
|
30˚
|
.57
|
.95
|
|
40˚
|
.83
|
1.38
|
|||
50˚
|
1.19
|
1.98
|
|||
10˚
|
.17
|
.29
|
|||
20˚
|
.36
|
.63
|
|||
20˚
|
1.06
|
30˚
|
.57
|
.99
|
|
40˚
|
.83
|
1.45
|
|||
50˚
|
1.19
|
2.08
|
|||
10˚
|
.17
|
.32
|
|||
1.66//
|
20˚
|
.36
|
.68
|
||
30˚
|
1.15
|
30˚
|
.57
|
1.08
|
|
40˚
|
.83
|
1.57
|
|||
50˚
|
1.19
|
2.26
|
|||
10˚
|
.17
|
.36
|
|||
20˚
|
.36
|
.77
|
|||
40˚
|
1.30
|
30˚
|
.57
|
1.22
|
|
40˚
|
.83
|
1.78
|
|||
50˚
|
1.19
|
2.55
|
|||
10˚
|
.17
|
.43
|
|||
20˚
|
.36
|
.92
|
|||
50˚
|
1.55
|
30˚
|
.57
|
1.46
|
|
40˚
|
.83
|
2.13
|
|||
50˚
|
1.19
|
3.05
|
PROERTIES:
1. The
equator and all the meridians are being projected as straight line.
2. The
other parallels are projected as curve.
3. The
scale of the meridian and parallels are not true.
4. The
amount of exaggeration is increasing away from the centre of the projection.
USES:
This projection can be used mainly for drawing
maps of small areas along any part of the equator.
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